Question

find the zeros of the quadratic polynomial 6x²-x-2 and verify the relationship between the zeros and coefficients​

Answer 1

Step-by-step explanation:

=

$= 6{x}^{2} - x - 2 \\ = > (factorize) \\ 12x { \\}^{2}$

12x^2 can be written as "3x-4x"

$6 {x}^{2} + 3x - 4x - 2 \\ 3x(2x + 1) - 2(2x - 1)$

$(3x - 2)(2x + 1)$

therefore,,

$x = \frac{2}{3} \: \: \: x = \frac{ - 1}{2}$

hope this helps

Answer 2

Answer:

For answer, see the given image.

Step-by-step explanation:

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