(4x/5-2)^3 factorise
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0
Answer:
x−3
x−2
+
x−5
x−4
=
3
10
⇒
(x−3)(x−5)
(x−2)(x−5)+(x−4)(x−3)
=
3
10
⇒
x
2
−5x−3x+15
x
2
−5x−2x+10+x
2
−3x−4x+12
=
3
10
⇒
x
2
−8x+15
2x
2
−14x+22
=
3
10
⇒
x
2
−8x+15
2(x
2
−7x+11)
=
3
10
⇒
x
2
−8x+15
x
2
−7x+11
=
3
5
⇒ 3x
2
−21x+33=5x
2
−40x+75
⇒ 2x
2
−19x+42=0
⇒ 2x
2
−12x−7x+42=0
⇒ 2x(x−6)−7(x−6)=0
⇒ (x−6)(2x−7)=0
⇒ x−6=0 and 2x−7=0
⇒ x=6 and x=
2
7
∴ We can see, roots given in question are correct.
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