(4x-5)(x+2)=(x+3)(x+1)
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Answered by
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Hey friend...!!! here's your answer
__________________________
(4x - 5)(x + 2) = (x + 3)(x + 1)
4x^2 + 8x -5x - 10 = x^2 + x + 3x + 3
3x^2 - x - 13 = 0
____________________
#Hope its help you dear#
☺
__________________________
(4x - 5)(x + 2) = (x + 3)(x + 1)
4x^2 + 8x -5x - 10 = x^2 + x + 3x + 3
3x^2 - x - 13 = 0
____________________
#Hope its help you dear#
☺
Answered by
0
Hey
Here is your answer
(4x-5)(x+2)=(x+3)(x+1)
4x^2 +8x -5x -10 = x^2 + x +3x +3
4x^2 -x^2 +3x -10=4x +3
3x^2-x-13=0
Hope it helps you q
Here is your answer
(4x-5)(x+2)=(x+3)(x+1)
4x^2 +8x -5x -10 = x^2 + x +3x +3
4x^2 -x^2 +3x -10=4x +3
3x^2-x-13=0
Hope it helps you q
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