Question

(4x – 5y)^2
pls help thks

Answer 1

Answer:

16 x 2 − 40xy + 25y2

Step-by-step explanation:

= (4x+−5y) (4x+−5y)

=(4x) (4x) + (4x) (−5y) + (−5y) (4x ) +(−5y) (−5y)

= 16 x 2 − 20xy − 20xy + 25y2

= 16 x 2 − 40xy + 25y2

please mark brainliest

Answer 2

$\underline{\large{\tt{Answer}}}$

$= \tt16 {x}^{2} + 25 {y}^{2} - 40xy$

Solution

In order to solve the eq ( 4x - 5y )² note the algebraic Identity used :

• (a - b)² = a² + b² - 2ab

Take a = 4x ; b = 5y

Thus ,

$\footnotesize\tt(4x - 5y) = {(4x)}^{2} + {(5y)}^{2} - 2 \times 4x \times 5y$

$: \longrightarrow \footnotesize \bf16 {x}^{2} + 25 {y}^{2} - 40xy$

$\rule{200pts}{2pts}$

Additional Algebraic Identity :

$\tt{(a + b)}^{2} = {a}^{2} + {b}^{2} + 2ab$

$\tt{(a - b)}^{2} = {a}^{2} + {b}^{2} - 2ab$

$\tt(a + b)(a - b) = {a}^{2} - {b}^{2}$

$\tt {(a + b)}^{2} + (a - b)^{2} = 2( {a}^{2} + {b}^{2} )$

$\tt {(a + b)}^{2} - (a - b)^{2} = 4ab$

$\bf Thankyou$