4x+6>8x-2
(a) x is real number
(b) x is integer
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Answered by
6
=>4x+6>8x-2
=>8x-4x -2-6 <0
=>4x -8 <0
=>4(x-2)<0
therefore , x <2 so, (b) x is integer
=>8x-4x -2-6 <0
=>4x -8 <0
=>4(x-2)<0
therefore , x <2 so, (b) x is integer
shorrya1618:
thank u
Answered by
3
Given :
4 x + 6 > 8 x - 2
==> 4 x + 6 - 8 x + 2 > 0
==> 4 x - 8 x + 6 + 2 > 0
==> - 4 x + 8 > 0
==> - 4 x > 0 - 8
==> - 4 x > - 8
Dividing both sides by - 4 will change the sign :
==> x < - 8 / - 4
==> x < 2.
Hence :
x is both real number and integer .
x = { 2 , 1`, 0 , - 1, ..................... }
Hope it helps !
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