Question

4x+6y=3xy
8x-19y= 5xy​

Answer 1

Answer:

(4x+6y=3xy)×2

8x+12y=6xy

eq1-eq2

==>8x+12y=6xy

(-)8x+19y=5xy

31y=11xy

y/xy=11/31

1/x=11/31

x=31/11

Answer 2

The value of x and y is 4.5 and 2.4

Step-by-step explanation:

$\ Given \ value:\\\\4x+6y=3xy.....(i) \\\\8x-19y= 5xy.....(ii)\\\\\ Find:\\\\x \ and \ y =?\\\\\ Solution:\\\\\ Solve \ equation \ (i)\\\\4x+6y=3xy \\\\\rightarrow 4x=3xy-6y\\\\\rightarrow 4x=3y(x-2)\\\\\rightarrow y=\frac{4x}{3(x-2)}\\\\\ put \ the \ value \ of \ y \ in \ equation \ (ii)\\\\\ equation\\\\8x-19y= 5xy\\\\\rightarrow 8x-19\times \frac{4x}{3(x-2)}=5 \times x \times \frac{4x}{3(x-2)} \\\\\rightarrow 8x-\frac{76x}{3(x-2)}=\frac{20x^2}{3(x-2)}$

$\rightarrow \frac{8x \times3(x-2) -76x}{3(x-2)}=\frac{20x^2}{3(x-2)} \\\\\rightarrow \frac{ 24x^2-42x -76x}{3(x-2)}=\frac{20x^2}{3(x-2)} \\\\\rightarrow (24x^2-42x -76x)=(20x^2) \\\\\rightarrow 24x^2-42x -76x-20x^2=0 \\\\\rightarrow 4x^2-118x=0\\\\\rightarrow x=\frac{118}{4}\\\\\ put \ the \ value \ of \ x \ in \ equation \ (i)\\\\4 \times \frac{18}{4} +6y = 3 \times \frac{18}{4} \times y\\\\18+6y= \frac{54}{4}y18=\frac{54}{4}y-6y\\\\18=\frac{54y-24y}{4}\\\\72=30y \\\\y= \frac{72}{30}$

$y= \frac{24}{10}\\\\y= 2.4$

$x=\frac{18}{4} = 4.5$

Learn more:

• Find the value: https://brainly.in/question/8972486