Question

4x square + 40x+84=0
Chhota x=
Bada x=​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Larger\:x=-3}}}$

$\green{\tt{\therefore{Smaller\:x=-7}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies {4x}^{2} + 40 + 84 = 0 \\ \\ \red{\underline \bold{To \: Find:}} \\ \tt: \implies Larger \: x = ? \\ \\ \tt: \implies Smaller \: x=?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies {4x}^{2} + 40 + 84 = 0 \\ \\ \text{Dividing \: both \: side \: by \: 4}\\ \tt: \implies \frac{4 {x}^{2} }{4} + \frac{40}{4} x + \frac{84}{4} = 0 \\ \\ \tt: \implies {x}^{2} + 10x + 21 = 0 \\ \\ \tt: \implies {x}^{2} + 7x + 3x + 21 = 0 \\ \\ \tt: \implies x(x + 7) + 3(x + 7) = 0 \\ \\ \tt: \implies (x + 3)(x + 7) = 0 \\ \\ \green{\tt: \implies x = - 3 \: and \: - 7} \\ \\ \green{\tt \therefore Larger \: x = - 3} \\ \\ \green{\tt \therefore Smaller\: x = - 7}$

Answer 2

Step-by-step explanation:

$\bf \huge\:\: Question \:$

• 4x square + 40x+84=0
• Chhota x=
• Bada x=

___________________________

$\bf \huge\:\: Given \:$

• 4x square + 40x+84=0

__________________________

$\bf \huge\:\: To \: Find$

• Chhota x=
• Bada x=

__________________________

$\bf \huge\:\: Solution\:$

$\bf\:\:4X^2+40x+84=0\:$

$\bf\:\:On \:\:similars$

$\bf\:\:4(x^2+10x+21)=0\:$

$\bf\:\: x^2+10x+21=0\:$

$\bf\:\:x^2+7x+3x+21=0\:$

$\bf\:\:x(x+7)+3(x+7)=0\:$

$\bf\:\:(x+3)(x+7)=0\:$

$\bf\:\:x = -3 \:and\: x= -7\:$

HENCE

$\bf\:\red{chhota \:x = -3}\:$

$\bf\:\red{Bada \:X =-7}\:$