Math, asked by salonichaudhary639, 15 days ago

4x square - 4x -3 + 1
find the zeros​

Answers

Answered by priyel
0

Step-by-step explanation:

 {4x}^{2} - 4x - 3 + 1 \\  \\   \bf\implies:   {4x}^{2}  - 4x - 2 \\  \\ \bf\implies:   {2x}^{2}  - 2x - 1 \\  \\ x =  \frac{ - b \pm \sqrt{ {b}^{2} - 4ac }  }{2a}  \\  \\ \bf\implies:  x =  \frac{ - ( - 2) \pm \sqrt{ {( - 2)}^{2}  - 4.2.1} }{2.2}  \\  \\ \bf\implies:  x =  \frac{2 \pm \sqrt{4 - 8}}{4}  \\  \\ \bf\implies:  x =  \frac{2 \pm \sqrt{ - 4} }{4}  \\  \\ \bf\implies:  x =  \frac{2 \pm 4i}{4}  \:  \:  \:  \:  \red {\: i = \sqrt{ - 1}} \\  \\ \bf\boxed{x =  \frac{2 + 4i}{4} }\:  \:  \: \boxed{x =  \frac{2 - 4i}{4} }

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