Question

4x square +y square+ z square-4xy-2yz-4xz

Answer 1

Step-by-step explanation:

4x²+y²+z²-4xy-2yz-4xz

4x²-4xy+y²-2yz+z²-4xz

4x(x-y) +y(y-2z)+z(z-4x)=0

is the answer of this question

Answer 2

HERE IS UR ANSWER DEAR,

$= 4 {x}^{2} + {y}^{2} + {z}^{2} - 4xy + 2yz - 4xz$

$= {( 2x)}^{2} + {( - y)}^{2} + {( - z)}^{2} +2 (2x)( - y) +2 ( - y)( - z) +2(2x)( - z)$

$it \: is \: in \: the \: form \: of \ {(a + b + c)}^{2} = {a}^{2} + {b}^{2} {c}^{2} + 2ab + 2bc + 2 ac$

$therefore$

$by \: comparing \: we \: conclude$

$= (2x - y - z)$

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