4x+y= 13and and 2x-3y=3 in elimination
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Given :
4x + y = 13
2x - 3y = 3
Required to find :
- Values of x and y using elimination Method
Solution :
Let consider ;
4x + y = 13 ---------> equation 1
similarly,
2x - 3y = 3 ----------> equation 2
Now , let's solve this question using elimination method
So;
Let's multiply equation 2 with 2
That is
2( 2x - 3y ) = 2 (3)
4x - 6y = 6 -------------> equation 3.
Let this be equation 3
Hence solving this question is simple.
Now subtract equation 1 and equation 3
Therefore,
4x + 1y = 13
4x - 6y = 6
(-) (+) (-)
-----------------
0 + 7y = 7
7y = 7
y = 7/7
y = 1
Therefore,
Value of y is 1 .
Using this value of y let's find the value of x.
Hence substitute this value of y in equation 1 .
4x + 1y = 13
4x + 1 = 13
4x = 13 - 1
4x = 12
x = 12/4
x = 3 .
At last;
Therefore value of x = 3
value of y = 1
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