Question

4x2  2(a2  b2 ) x  a2b2  0 9x2  9(a  b) x  (2a2  5ab  2b2 )  0 4x2  4a2 x  (a4  b4 )  0 x2 – x – 156 = 0 z2 – 32z – 105 = 0 40 + 3x – x2 = 0 7x2 + 49x + 84 = 0 √3x2 + 10x - 8√3 = 0 √3x2 11x  6√3  0 pls do all by factorization and quadratic formula

Answer 1

Answer:

$What$ $is$ $your$ $question$

NEED FRIENDS

꧁ ☆ ℜ ₳ ᴍ ₳ Ķ  ☆ ꧂