Question

4x²+4√3x+k

find the value of k​

Answer 1

Step-by-step explanation:

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Answer 2

Answer :

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$\heartsuit$ $\sf{4x^2+4\sqrt3x+k=0}$

$\heartsuit$ $\bf{by \: determinant \:form:(⌒o⌒) }$

$\heartsuit$ $\sf{(4\sqrt3)^2-4(4)(k) =0}$

$\heartsuit$ $\sf{(48-16k=0)}$

$\heartsuit$ $\sf{16k=48}$

$\heartsuit$ $\sf{k=\dfrac{48}{16}}$

$\spadesuit$ $\sf{k=3}$

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