Question

4x2-4ax+(a2-b2) by factorisation method​

Answer 1

Step-by-step explanation:

The given quadratic equation is 4x2−4ax+(a2−b2)=0

4x2−4ax+(a+b)(a−b)=0

⇒4x2+[−2a−2a+2b−2b]x+(a−b)(a+b)=0

⇒4x2+(2b−2a)x−(2a+2b)x+(a−b)(a+b)=0

⇒4x2+2(b−a)x−2(a+b)x+(a−b)(a+b)=0

⇒2x[2x−(a−b)]−(a+b)[2x−(a−b)]=0

⇒[2x−(a−b)][2x−(a+b)]=0

⇒2x−(a−b)=0,2x−(a+b)=0

⇒x=2a+b,2a−b.

Answer 2

Step-by-step explanation:

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