Question

4x²+5√2x-3 solve using factorisation method
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Answer 1

Explanation:

We have polynomial is 4x²+5√2x-3

4x²+5√2x-3=0

a=4, b=5√2 ,c=-3 ,D=b²-4ac

D=(5√2)²-4x4x(-3)

D= 50+48

D=98

Apply Quadratic formula we got two zeros are

-b±√D/2a - 5✓2 +- ✓ 50+48/2*4 (-5✓2 +- ✓98)/8

therefore zeros of the polynomial are

(-5✓2 + ✓98)/8 & (-5✓2 - ✓98)/8