4x²-9 find the zero of the polynomial verify
Answers
Answered by
19
Zero of the polynomial,
=> 4x²- 9 = 0
=> 4x² = 9
=> x² = 9/4
=> x = ± ⅔
Verification-
= 4x²- 9
= 4(⅔)²- 9
= 4(9/4) - 9
= 9-9
= 0
Hence Verified
I hope this will help you.
=> 4x²- 9 = 0
=> 4x² = 9
=> x² = 9/4
=> x = ± ⅔
Verification-
= 4x²- 9
= 4(⅔)²- 9
= 4(9/4) - 9
= 9-9
= 0
Hence Verified
I hope this will help you.
Answered by
6
4x^2-9=(2x)^2-3^2
=(2x+3)(2x-3)
Therefore zeros are 3/2 & -3/2
Verification : for x=3/2
4x^2-9=(2×3/2+3)(2×3/2-3)
=(......)(3-3)
=(....).0=0
Similarly for x=-3/2
4x^2-9 = 0
=(2x+3)(2x-3)
Therefore zeros are 3/2 & -3/2
Verification : for x=3/2
4x^2-9=(2×3/2+3)(2×3/2-3)
=(......)(3-3)
=(....).0=0
Similarly for x=-3/2
4x^2-9 = 0
Similar questions