If A=3i+4j+5k
B=3i+4j-5k
Angle between A and B ?
Answer w/solution :)
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dot product of A & B is ABcosα ,where α is the angle between vector A &B
A.B=9+16+25=50
again
|A|=√50 |B|=√50
so cosα=1 so α=0
or
both A &B are parallel so angle =0
A.B=9+16+25=50
again
|A|=√50 |B|=√50
so cosα=1 so α=0
or
both A &B are parallel so angle =0
areebah:
But the answer is D=90 degrees :'f
I am sorry .I missed "-" sign in B .indeed angle is 90 degree.A &B are not parallel . A.B=
A.B=9+16-25=0 i.e A and B perpendicular to each other
sorry for that mistake.
No i got it . Thanks
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