4x2 + y2 + z2 - 4xy - 2yz + 4xz
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using identity (a+b+c)^2 = a^2+b^2+c^2+2ab+2bc+2ca
(2x)^2+(y)^2+(z)^2-2(2x)(y)-2(y)(z)+2(x)(z)
= (2x-y+z)^2
(2x)^2+(y)^2+(z)^2-2(2x)(y)-2(y)(z)+2(x)(z)
= (2x-y+z)^2
rishab260:
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