Question

4x³+5x-10 ; x-3 use synthetic division and find quotient and remainder.​

Answer 1

$\underline{\textbf{Given:}}$

$\mathsf{4x^3+ 5x-10 \;\div\;(x-3)}$

$\underline{\textbf{To find:}}$

$\textsf{The quotient and remainder}$

$\underline{\textbf{Solution:}}$

$\textsf{We apply synthetic division to find the quotient and remainder}$

$\underline{\textbf{Sythetic division:}}$

$\mathsf{\begin{array}{c|cccc}3&4&0&5&-10\\&&&&\\&&12&36&123\\\cline{2-5}&4&12&41&\boxed{113}\end{array}}$

$\mathsf{Then,}$

$\mathsf{Quotient=4x^2+12x+41}$

$\mathsf{Remainder=113}$