Question

4xy- x^ 2- 4y^2 +z^ 2​

Answer 1

${z}^{2} - ( {x}^{2} - 4xy + 4 {y}^{2} )$

$= {z}^{2} - (x - 2y) {}^{2}$

$= (z + x - 2y)(z - x + 2y)$