Question

4y+1/3+2y-1/2-3y-7/5=47/10​

Answer 1

Answer:

$4y + \frac{1}{3} + 2y - \frac{1}{2} - 3y - \frac{7}{5} = \frac{47}{10} \\ solving \: y \: and \: numbers \\ 3y + \frac{47}{30} = \frac{47}{10} \\ 3y = \frac{94}{30} \\ y = \frac{94}{90} = \frac{47}{45}$

Answer 2

:. y = 94 / 45

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