4y-3x-23=0
3y+4x-11=0
By cross multiplication method
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Answer:
_3x+4y=23
______________
4x+3y=11
by cross multiplying
11(_3x+4y)=23(4x+3y)
_33x+44y=92x+69y
_33x_92x=69y_44y
_125x=25y
y=_125x/25=_5x
y=_5x substitute in (1)equation
_3x+4(_5x)_23=0
_3x_20x_23=0
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