Math, asked by Happy6225, 11 months ago

4y-3x-23=0
3y+4x-11=0
By cross multiplication method

Answers

Answered by kavitha54
14

Answer:

_3x+4y=23

______________

4x+3y=11

by cross multiplying

11(_3x+4y)=23(4x+3y)

_33x+44y=92x+69y

_33x_92x=69y_44y

_125x=25y

y=_125x/25=_5x

y=_5x substitute in (1)equation

_3x+4(_5x)_23=0

_3x_20x_23=0

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