Math, asked by trishank4, 10 months ago


4y2-4y+1
(iv) 18a2 - 50

Answers

Answered by amitnrw
8

Answer:

4y² - 4y  + 1 = (2y-1)²

18a² - 50 = 2(3a + 5)(3a - 5)

Step-by-step explanation:

4y2-4y+1

(iv) 18a2 - 50

4y² - 4y  + 1

= 4y² -2y - 2y + 1

= 2y(2y-1) -1(2y -1)

= (2y-1)(2y-1)

= (2y-1)²

4y² - 4y  + 1 = (2y-1)²

18a² - 50

= 2*9a² - 2*25

= 2*(3a)² - 2*(5²)

= 2 ( (3a)² - (5²))

= 2(3a + 5)(3a - 5)

18a² - 50 = 2(3a + 5)(3a - 5)

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