4y2-4y+1
(iv) 18a2 - 50
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Answer:
4y² - 4y + 1 = (2y-1)²
18a² - 50 = 2(3a + 5)(3a - 5)
Step-by-step explanation:
4y2-4y+1
(iv) 18a2 - 50
4y² - 4y + 1
= 4y² -2y - 2y + 1
= 2y(2y-1) -1(2y -1)
= (2y-1)(2y-1)
= (2y-1)²
4y² - 4y + 1 = (2y-1)²
18a² - 50
= 2*9a² - 2*25
= 2*(3a)² - 2*(5²)
= 2 ( (3a)² - (5²))
= 2(3a + 5)(3a - 5)
18a² - 50 = 2(3a + 5)(3a - 5)
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