Math, asked by SOHAMMONDAL76, 2 days ago

4yz(z^2 + 6z - 16) divided by 2y(z + 8)

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Answers

Answered by abhimanyusingh00355
1

Answer:

2z(z – 2) hope you like this

Answered by krishpmlak
1

Answer:

Step-by-step explanation:

Given that,

4yz ( z² + 6z - 16 ) / 2y (z + 8)

= 4yz ( z² + 8z - 2z - 1616 ) / 2y (z + 8 )

= 4yz [ z ( z + 8 ) - 2 ( z + 8 ) ] / 2y ( z + 8 )

= 4yz ( z - 2 ) ( z + 8 ) / 2y( z + 8

= 2z ( 2y ) ( z - 2 ) ( z + 8 ) / 2y ( z + 8 )

= 2z ( z- 2 ) is the answer.

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