a cube of 70 cm side is divided into 3 equal cubes find its area of the each of the sectors
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Three equal cubes are placed adjacently in a row. Find the ratio of the total surface area of the resulting cuboid to that of the sum of the total surface areas of the three cubes.
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Correct option is C)
Given, three cube are placed adjacent in a row to form a cuboid.
Let the side of cube be a, three cube placed in row then breadth of cuboid be a, length of cuboid is 3a, height of cuboid is a.
Sum of total surface area of three cubes =6a
2
+6a
2
+6a
2
=18a
2
Total surface area of resulting cuboid =2(lb+bh+lh)
=2(3a×a+a×a+3a×a)
=2(7a
2
)
=14a
2
Ratio of total surface area of cuboid to that of cube =
18a
2
14a
2
=
9
7
=7:9
Answer:
Your answer is 7:9
Step-by-step explanation:
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