Question

4z+3/3+1/3=3z-1/2 answer z=11 ayega to ose me brainlist me mark karuga promise​

Answer 1

$\huge {\boxed {\mathbb {QUESTION}}}$

$4z+\frac{3}{3}+\frac{1}{3}=3z-\frac{1}{2}$

$\huge {\boxed {\mathbb {ANSWER}}}$

$\implies 4z+\frac{3}{3}+\frac{1}{3}=3z-\frac{1}{2}$

$\implies 4z+\cancel {\frac{3}{3}} +\frac{1}{3}=3z-\frac{1}{2}$

$\implies 4z+1+\frac{1}{3} =3z-\frac{1}{2}$

$\implies 4z+\frac{3+1}{3} =3z-\frac{1}{2}$

$\implies 4z+\frac{4}{3} =3z-\frac{1}{2}$

$\implies 4z-3z=-\frac{4}{3}-\frac{1}{2}$

$\implies 4z-3z=\frac{-8-3}{6}$

$\implies {\boxed {\boxed {z=-\frac{11}{6}}}}$

$\huge {\boxed {\mathbb {HOPE \:IT \:HELPS \:YOU }}}$

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$\huge {\boxed {\mathbb {EXTRA\:INFORMATION}}}$

$LCM$

$The\: least \:common \:multiple\:, lowest\: common\\ multiple\:, or \:smallest\: common\: multiple\: of\: two\\ integers\: a \:and\: b$

$HCF$

$The \:highest\: common\: factor\: is\: found\: by\\ finding\: all \:common\: factors\: of\: two\: numbers\: and\\ selecting \:the\: largest\: one.$

${\mathbb{\colorbox {orange} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {lime} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {aqua} {@suraj5070}}}}}}}}}}}}}}}$

Answer 2

Answer:

4z+1+1/3=3z-1/2

4z+4/3=3z-1/2

4z-3z=-4/3-1/2

z=-11/6

you wrong answer is -11/6