Question

5.0 g of water at 25 °C is dropped onto a large block of ice at 0 °C. The water cools to 0 °C and some of the icemelts.
Assume that all the energy lost by the water is gained by the ice. What is the mass of ice thatmelts?
Thespecific heat capacity of water is4.2J/(g°C).
Thespecificlatentheatoffusionoficeis 340J/g.

Answer 1

1.235g of ice melts

Step-by-step explanation:

Heat released by water= 5*25*4.2 =420 J

Now

ice accepts this heat

So 420 = m* 340

=>m = 420/340= 1.235 g

Answer 2

Answer:

1.5g of ice melts

Explanation:

The heat released by water = m x c x change in temperature

                                              =  5 x 4.2 x 25 = 525 J

Specific latent heat = Thermal energy / Mass of the ice

Mass of the ice = Thermal energy / specific heat capacity

                          = 525 / 340

            Answer = 1.5g of ice melts