5.0 lit of 0.4Msulfuric acid contain how many mole of sulfuric acid
aastha15das:
can u plz tell me question clearly
Answers
Answered by
2
We know that,
Molarity(M) = moles(n)/volume(vol)
Given,
M = 0.4
Vol = 5
0.4 =moles(n)/5
n = 0.5 x 4
n = 2
Hope it helps!
Molarity(M) = moles(n)/volume(vol)
Given,
M = 0.4
Vol = 5
0.4 =moles(n)/5
n = 0.5 x 4
n = 2
Hope it helps!
my answer is correct
Answered by
2
0.4 0.4
M or 0.4 0.4
moles are present in 1L solution.
=> In 5L 5L moles moles =
0.4×5=2 0.4×5=2 moles.
hope it helps
Thanks for helping :)
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