Question

√5 +1/√5-1 + √5-1/√5+1=a+b√5 find the values of a and b?

Answer 1

Answer:

a=3 and b=0

Step-by-step explanation:

$\frac{\sqrt{5}+1}{\sqrt{5}-1}+\frac{\sqrt{5}-1}{\sqrt{5}+1}=a+b\sqrt{5}$

$\frac{(\sqrt{5}+1)^2+(\sqrt{5}-1)^2}{(\sqrt{5}-1)(\sqrt{5}+1)}=a+b\sqrt{5}$

$\frac{(\sqrt{5}+1)^2+(\sqrt{5}-1)^2}{5-1}=a+b\sqrt{5}$

$\frac{5+1+2\sqrt{5}+5+1-2\sqrt{5}}{4}=a+b\sqrt{5}$

$\frac{12+0\sqrt{5}}{4}=a+b\sqrt{5}$

$3+0\sqrt{5}=a+b\sqrt{5}$

comparing both sides we get

a=3 and b=0

Answer 2

Answer:

here is ur answer

Step-by-step explanation:

may it's helpful for u