Question

5)
1 is a zero of the polynomial P(X). ax^2-3(a-1)-1,then
nd the value of a
1
2
.3
4​

Answer 1

Answer:

Step-by-step explanation:

Substitute x = 1

$p(x)=ax^{2} -3(a-1)-1\\p(1)=0 \\a(1)^{2}-3(a-1)-1=0\\a -3a +3-1=0\\-2a=-2\\a=1$

Hope this helps u mate :)

Answer 2

Answer:

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