Question

5. 10% of x + 20% of y = 24
3x - y = 20 by the method of elimination by equating coefficient ​

Answer 1

Answer:

Hi ,

10% of x + 20% of y = 24

=> ( 10/100 )x + ( 20/100 ) y = 24

=> ( 10/100 ) [ x + 2y ] = 24

=> ( 1/10 ) ( x + 2y ) = 24

=> x + 2y = 240 -----( 1 )

3x - y = 20

=> y = 3x - 20 ---( 2 )

Substitute y = 3x - 20 in equation ( 1 )

x + 2( 3x - 20 ) = 240

=> x + 6x - 40 = 240

=> 7x = 240 + 40

=> 7x = 280

x = 280/7

x = 40

Substitute x = 40 in equation ( 2 ),

we get

y = 3 × 40 - 20

y = 120 - 20

y = 100

Therefore ,

x = 40 , y = 100

I hope this helps

Or

(10/100)x+(20/100)y=24

(1/10)x+(1/5)y=24

(x/10)+(y/5)=24

2(x+3y/10)=24

x+6y/10=24

x+6y=24×10

x+6y=240

x=240÷6

x=40

It's substitute

3x-y=20

3×40-y=20

120-y=20

-y=20-120

y=100

Answer 2

sorry bro i dont full, i know half only