5,11,17......
Find if 301 is a term?
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हलो मित्र,
The terms in the AP are 5+0*6, 5+1*6, 5+2*6, 5+3*6, etc. If 301 is a term, it must be of the form 5+n*6. Set this equal to 301 and solve for n. n needs to be a whole number.
5+n*6 = 301
n*6 = 296
n = 296/6.
296 must be divisible by 6, so it must be divisible by both 2 and 3, the factors of 6.
296 is even so it is divisible by 2. However, the digits in 296 add to a number that is not divisible by 3 (2 + 9 +6 = 17, which is prime and not divisible by 3, so 296 is not divisible by 3.)
Since n is not a whole number, 301 is not a term in the AP.
The terms in the AP are 5+0*6, 5+1*6, 5+2*6, 5+3*6, etc. If 301 is a term, it must be of the form 5+n*6. Set this equal to 301 and solve for n. n needs to be a whole number.
5+n*6 = 301
n*6 = 296
n = 296/6.
296 must be divisible by 6, so it must be divisible by both 2 and 3, the factors of 6.
296 is even so it is divisible by 2. However, the digits in 296 add to a number that is not divisible by 3 (2 + 9 +6 = 17, which is prime and not divisible by 3, so 296 is not divisible by 3.)
Since n is not a whole number, 301 is not a term in the AP.
anshul00157:
wrong here we add 6 not multiply.
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