Question

واعر ( 5 - (2) ((له -22 e
$2 {x}^{2} - 3x - 5 ka \: ek \: sunyak \: hai$

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Answer 1

Answer:

Required Answer :-

By splitting the middle term

${2x}^{2} - 3x - 5 = 0$

$= {2x}^{2} + 2x - 5x - 5 = 0$

$= 2x(x + 1) - 5(x + 1) = 0$

$= ( x + 1)(2x - 5) = 0$

Finding Roots :-

First Root

$x + 1 = 0$

$x = - 1$

Second Root :-

$2x - 5 = 0$

$2x = 5$

$x = \frac{5}{2}$

Therefore the two roots are -1 and 5/2