The present age of father is 3 times the age of his son. After 20 years , the age of father will become 2 times the age of his son.
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Given that Father's age is three times the age of his two sons. Now, it is also given, after 5 years, his age will be twice the sum of the ages of his son. Therfore, after 5 years age of father will be 3(x+y)+5 and age of the sons will be x+5 and y+5. Thus the age of the father is 45.
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Answer:
x = 60, y = 20
Step-by-step explanation:
Given x = 3y
x+20 = 2(y+20)
3y+20 =2y+40
3y-2y = 40-20
y =20
x = 3(20)=60
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