5(2)
Find x
show the working pls
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☆ Hello Friend ☆
As shown in diagram Triangle ADC is an isosceles triangle
So Two angles that is Angle DAC and ADC are equal.
ACD+130°= 180°
ACD= 180°-130°
ACD= 50°
x+50°+50°= 180°
2x=180°-100°
x=80°
x= 80°
80°+ADC=180°
ADC= 180°-75°
= 100°
Similarly triangleADC is an isosceles triangle
x+x+100°= 180°
2x=80°
x=80/2 = 40°
Hooe it helps☺
As shown in diagram Triangle ADC is an isosceles triangle
So Two angles that is Angle DAC and ADC are equal.
ACD+130°= 180°
ACD= 180°-130°
ACD= 50°
x+50°+50°= 180°
2x=180°-100°
x=80°
x= 80°
80°+ADC=180°
ADC= 180°-75°
= 100°
Similarly triangleADC is an isosceles triangle
x+x+100°= 180°
2x=80°
x=80/2 = 40°
Hooe it helps☺
aditya2020222003:
ans is 40°
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