Question

5.249 of metallie.earbonate on being strongly
heated liberates, 1309.28 ml of co2 at 27c and
750 mm pressure of Hg?
find the equivalent mass of the metal
​

Answer 1

let, at 27∘C temperature and 755 mmHg pressure,

volume of 1309.28 mL CO2 gas at STP be V mL, then

755×1309.28/(273+27)=760×V/273 [∵P1V1/T1=P2V2/T2]

or, V=1183.6mL

At STP, mass of 22400 mL CO2 gas=44g

∴ At STP, 1183.6 mL CO2 gas =44/22400×1183.6=2.325g

(mass of metallic carbonate)/(mass of CO2 produced )

=(equivalent mass of metallic carbonate)/(equivalent mass of CO2)

or, 5.249/2.325=(E+30)/22 [E=equivalent mass of the metal]

Equivalent mass of CO2−3=60/2=30 [Equivalent mass of 442=22]

∴E=19.66≈20

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