Math, asked by arun8jul, 7 months ago

5^2x÷5^-3=5^5,please solve fast its urgent

Answers

Answered by Thoroddinson
4

Answer:

1

Step-by-step explanation:

As 5^2x÷5^-3=5^5

=5^(2x+3) =5^5

As base are same we can compare powers

2x+3 =5

2x=2

x=1

Please mark me as brainliest

Answered by tripathyspandan23
0

Step-by-step explanation:

5^(2x) - 5^(x + 3) + 125 = 5^(x)

5^(2x) - 5^3 * 5^(x) + 125 = 5^x

5^(2x) - 125 * 5^(x) - 5^(x) + 125 = 0

5^(2x) - 126 * 5^(x) + 125 = 0

5^(x) = (126 +/- sqrt(126^2 - 4 * 1 * 125)) / (2 * 1)

5^(x) = (126 +/- sqrt(15876 - 500)) / 2

5^(x) = (126 +/- 124) / 2

5^(x) = 250/2 , 2/2

5^(x) = 125 , 1

x * ln(5) = ln(125) , ln(1)

x * ln(5) = ln(5^3) , 0

x * ln(5) = 3 * ln(5) , 0

x = 3 * ln(5) / ln(5) , 0 / ln(5)

x = 3 , 0

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