Math, asked by ayeshakhatun10501, 4 months ago

√5/(√3+√2)-3√3/(√2+√5)+2√2(√3+√5)​

Answers

Answered by Anonymous
0

\frac{√5}{(√3+√2)} - \frac{3√3}{(√2+√5)}+ \frac{2√2}{(√3+√5)}\\\\\frac{√5(√3-√2)}{3-2} - \frac{3√3(√2-√5)}{2-5} + \frac{2√2(√3-√5)}{3-5}\\\\\frac{√5(√3-√2)}{1} - \frac{3√3(√2-√5}{-3} + \frac{2√2(√3-√5)}{-2}\\\\√5(√3-√2) + √3(√2-√5) - √2(√3-√5)\\\\\cancel{√5√3} - \cancel{√5√2} + \cancel{√3√2 }- \cancel{√3√5} - \cancel{√2√3} + \cancel{√2√5}\\\\0

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