Question

√5+√3÷√5-√3=?..................​

Answer 1

$\mathfrak{\huge{\red{QUESTION}}}$

Given

$<font color = "blue"><marquee>ANSWER WITH FULL SOLUTION</font color = "blue"></marquee>$

$\frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} - \sqrt{3} } \\ \\ = \geqslant rationalising \: the \: denominator \\ \\ = \geqslant \frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} - \sqrt{3} } \times \frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} + \sqrt{3} } \\ \\ = \geqslant \frac{( \sqrt{5} + \sqrt{3}) {}^{2} }{ (\sqrt{5} ) {}^{2} - ( { \sqrt{3} )}^{2} } \\ \\ = \geqslant \frac{ \sqrt{5 {}^{2} } + \sqrt{3 {}^{2} } + 2 \times \sqrt{5} \times \sqrt{3} }{5 - 3} \\ \\ = \geqslant \frac{5 + 3 + 2 \sqrt{15} }{2} \\ \\ = \geqslant \frac{8 + 2 \sqrt{15} }{2} \\ \\ = \geqslant 4 + 2 \sqrt{15}$

Answer 2

Step-by-step explanation:

Rationalise the denominator and then multiply the numerator