Question

5.3 into 10 to the power 11 electrons are flowing through the filament of bulb for 2 minutes find the current​

Answer 1

Answer:

I = Q/t

= 5.3×10-¹¹/2×60

= 4.416×10^-9 A

Answer 2

Answer:

5.3 into 10 to the power 11 electrons are flowing through the filament of bulb for 2 minutes, the current​ will be $7.1\times 10^{-10} A$

Explanation:

• Let I be the current flowing through an electrical circuit t be the time of flow and Q be the total charge.  

        We have the expression for the total charge as,

        $Q = It$    

        That is,

        $I = \frac{Q}{t}$       ...(1)

        Then we have another expression for Q as,

         $Q = ne$     ...(2)

        Where n is the number of electrons and e is the charge of one electron.

        We can use these equations for solving the given question.

• From the question,

       Number of electrons $n =5.3\times 10^{11}$

       Time, $t = 2min = 2\times 60 = 120s$

       Charge on an electron, $e = 1.6\times 10^{-10} C$

        Then,

        Substituting the given values into equation (2)

        $Q = 5.3\times 10^{11} \times 1.6\times10 ^{-19}=8.48\times 10^{-8}C$

        Now, Using equation(1),

        $I = \frac{8.48\times10^{-8}}{120} = 7.1\times10^{-10} A$