Question

the perimeter of rectangle is 66 and one of its side is 18 find its area​

Answer 1

Answer:

Given that the perimeter of rectangle is 66

And one of its side is 18

So we need to find its area

perimeter of a rectangle=2×(l+b)=66 units

One side may be length or breadth

So let's take as length,l=18 units

2×(l+b)=66

2×(18+b)=66

36+2b=66

2b=66-36

2b=30

b=15

So l=18 uts,b=15 uts

We know that Area of a rectangle=l×b

Area=18×15 sq.its

Area=270sq.uts

Area is 270 sq.uts

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Answer 2

Step-by-step explanation:

Perimeter of the rectangle = 66

One side = 18 the other side = 66/2 = 33

then 33 - 18 = 15

So, the area of the rectangle = 18 ×15

=270