Math, asked by Ashnagarg, 9 months ago

(5-3i) ^3
a + ib

Answers

Answered by SupriyaKharat
1

Answer:

-(10+198i)

Step-by-step explanation:

(5-3i)(5-3i)(5-3i)

[5(5-3i)-3i(5-3i)](5-3i)

[25-15i-15i+9(-1)](5-3i)

(16-30i)(5-3i)

16(5-3i)-30i(5-3i)

80-48i-150i+90(-1)

(80-90)-(48+150)i

-10-198i

-(10+198i)

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