5(3x+y)square + 6(3x+y)-8
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5(3x+y)^2+6(3x+y)-8
=5(9x^2+6xy+y^2)+(18x+6y)-8
=45x^2+30xy+5y^2+18x+6y-8
=45x^2+5y^2+18x+6y+30xy-8
mysticd:
it is wrong
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Answer:
5(3x+y)^2+6(3x+y)-8
Step-by-step explanation:
Putting (3x+ y)=z in the given expression.
5z^2+6z-8
=5z^2+10z-4z-8
=5z(z+2)-4(z+2)
=(z+2)(5z-4)
=(3x+y+2)[5(3x+y)-4)
=(3x+y+2)(15x+5y-4)
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