5 - (3x2 - 2x) (6 - 3x2 + 2x)
[Hint. Put 3x2 - 2x = yl
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5 - (3x2 - 2x) (6 - 3x2 + 2x)
put (3x2 - 2x) = y
= 5 - y (6-y)
= 5 - 6y + y^2
= y^2 - 5y - y + 5
= y( y - 5) - 1 (y - 5)
= (y-5) (y-1)
put the value of y
= (3x2 - 2x - 5) (3x2 - 2x - 1)
= (3x^2 - 3x + 5x - 5) (3x^2 - 3x + x - 1)
= {3x(x-1) + 5(x-1)} {3x(x-1) - 1(x-1)}
= (x-1) (3x+5) (x-1) (3x-1)
= (3x+5) (3x-1) (x-1)^2
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