Math, asked by plikhithreddy1234, 6 months ago

5) 40 students enter for a game of shot-put competition. The
distance thrown in metres) is recorded below.
(6)
Distance 12-13 13-14 14-15 15-16 16-17 17-18 18-19
in m
کی
9
12
9
4
2
1
No of
students
Use a graph paper to draw an ogive for the above
distribution. Use a scale of 2 cm = 1 m on one axis and
2cm = 5 students on the other axis. Hence using your
graph find:
(i) the median
(ii) upper quartile
iii) The inter-quartile range
(iv) The number of students who cover a distance which
is above 1612 m.​

Answers

Answered by amitnrw
7

Given : 40 students enter for a game of shot put competition

the distance thrown in metres   12-13 13-14 14-15 15-16 16-17 17 - 18  18-19

                             no of students  3        9        12        9     4          2         1

To Find :  mean

Solution:

distance   mid value   A=( mid value - 14.5)   f         A* f

12-13            12.5               -2                          3           -6

13-14             13.5                 -1                         9           -9

14-15            14.5                 0                         12           0

15-16            15.5                1                          9            9

16-17            16.5                2                          4             8

17 - 18          17.5                3                          2            6

18-19             18.5                4                          1             4

                                                                     40           12

14.5  +  12/40

= 14.5  + 0.3

= 14.8  

14.8 m is the mean distance

Median = 14 +  1 * ( 20 - 12) / 12

= 14.67 m

Learn More:

The mean of the following frequency distribution is 145 find the ...

brainly.in/question/12922397

mean of the sampling distribution = 200

brainly.in/question/15111066

Similar questions