Question

5. 4s2 is the configuration of the outermost orbit ofan element. Its atomic number would be :-(1) 29 (2) 24 (3) 30 (4) 19​

Answer 1

Answer:

Explanation:

Yeah the answer is 30

The reason behind this is:-

It cannot be 24 because if it is 24 and the outermost orbit will be 4s¹

Also it cannot be 29 because if it is 29 then the outermost orbit contains 4s¹

Atomic number 24 and 29 contains 4s¹ .. This is because of the extra stability rule of the element

And it cannot be atomic number 19 also because atomic number 19 that is Potassium does not have the one more electron to complete it's doublet 4s²

So finally your answer is 30

Hope it helps you

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