5) 5x + 2y = -3; x + 5y = 4
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5x + 2y = –3 .....(I)
x + 5y = 4 .....(II)
Multiply (II) with 5 we get
5x + 25y = 20 .....(III)
Subtracting (III) from (I) we get
5x−5x+2y−25y=−3−20
⇒−23y=−23
⇒y=−23−23=1
Putting the value of y = 1 in (II) we get
x+5(1)=4⇒x+5=4⇒x=4−5=−1
Thus, (x, y) = (−1, 1)
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