Question

5,6,9,14,21,30,41,?
​

Answer 1

Answer:

54

Step-by-step explanation:

$5 + 1 = 6 \\ 6 + 3 = 9 \\ 9 + 5 = 14 \\ 14 + 7 = 21 \\ 21 + 9 = 30 \\ 30 + 11 = 41 \\ 41 + 13 = 54$

Odd numbers are being added....

Answer 2

Answer:

Required next number is 54.

Step-by-step explanation:

Given,5,6,9,14,21,30,41,?

This is a problem of General inteligence part.

Here every numbers maintain a sequence.

If we notice carefully then we can see that sequence.

Now,

$5 + 1 = 6 \\ 6 + 3 = 9 \\ 9 + 5 = 14 \\ 14 + 7 = 21 \\ 21 + 9 = 30 \\ 30 + 11 = 41$

It is clear that we have added all consecutive odd numbers.

So, required next number is (41+13) = 54

This is a problem of General inteligence part of Mathematics.

Some important Mathematics formulas:

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \\ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3} \\ {x}^{3} + {y}^{3} = {(x + y)}^{3} - 3xy(x + y) \\ {x}^{3} - {y}^{3} = {(x - y)}^{3} + 3xy(x - y) \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ {x}^{2} + {y}^{2} = {(x - y)}^{2} + 2xy \\ {x}^{2} - {y}^{2} = {(x + y)}^{2} - 2xy \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ {x}^{3} + {y}^{3} = (x + y)( {x}^{2} - xy + {y}^{2} )$

Two more important Mathematics problem:

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

#SPJ2