Question

5.6 L of a gas at STP weighs 11 g Then gas may have the chemical formula

(A) C₂H6

(B) N₂O

(C) CO2

(D) Both B and C​

Answer 1

Answer:

N₂O

Explanation:

At S.T.P. 1 mole of a gas occupies a volume of 22.4 liters. Its mass will be equal to its molar mass.

The weight of 5.6 liters of a gas at S.T.P is 11 grams.

The weight of 22.4 litres of a gas at S.T.P will be 44 grams,

$11g \times \frac{22.4}{5.6} = 44 \: g$

The molar mass of nitrous oxide

(N₂O) is 14+14+16=44g/mol.

Hence, the gas is nitrous oxide

N₂O

I hope it is helpful

Answer 2

Explanation:

Given that :-

--- 5.6 L 5.6 L of a gas at STP weighs 11 g.

Using the formula :-

--- N2O

The solution is :-

--- This means that 5.6 litres of a gas at S.T.P. weigh 11 grams. So, the weight of 1 litre of the gas at S.T.P. is equal to 115.6 g. This weight must be equal to the molecular mass of the gas.

The Answer is :-

--- option (b) N2O

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