Question

5.6 L of oxygen at STP contains -
(1) 6.02 x 1023 atoms (2) 3.01 x 1023 atoms
(3) 1.505 x 1023 atoms (4) 0.7525 x 1023 atoms​

Answer 1

Answer:

22.4l=6.022 x 10^23 atoms

5.6l=y atoms

y=6.022 x 10^23 x5.6 divided by 22.4

y=33.7 x 10^23/22.4

y =1.505 x 10^23