Math, asked by asimali6605gmailcom, 10 months ago

5/6 of the girls and1/8of the boys are honor students what part of class consists of girls who are not honor students ​

Answers

Answered by venupillai
0

Answer:

I think some information is missing from the problem.

Step-by-step explanation:

The following is a general idea of how to do the sum. However, due to missing information, the final answer cannot be arrived at.

Fraction of girls that are honour students = 5/6

Fraction of boys that are honour students = 1/8

Fraction of girls that are NOT honour students = 1/6

Fraction of boys that are NOT honour students = 7/8

Let total number of girls in the class = x

Let total number of boys in the class = y

Total number of students = (x + y)

No. of honour student girls = 5x/6

No. of honour student boys = y/8

Total number of honour students = 5x/6 + y/8

Total number of non-honour students = (x +y) - (5x/6 + y/8) ....(i)

We can also get total number of non-honour students as:

No. of non-honour student girls = x/6

No. of non-honour student boys = y/6

Total number of non-honour students = (x/6 + y/6) ...(ii)

From (i) and (ii), we can get an equation connecting x and y. However, we will not be able to get x and y without more information (e.g. total number of girls, or boys, or students)

                                                               

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